2(f+5)=28

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Solution for 2(f+5)=28 equation: 



2(f+5)=28

We move all terms to the left:

2(f+5)-(28)=0

We multiply parentheses

2f+10-28=0

We add all the numbers together, and all the variables

2f-18=0

We move all terms containing f to the left, all other terms to the right

2f=18

f=18/2

f=9

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