2(d-5)-4=7(d+2)+2

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Solution for 2(d-5)-4=7(d+2)+2 equation: 



2(d-5)-4=7(d+2)+2

We move all terms to the left:

2(d-5)-4-(7(d+2)+2)=0

We multiply parentheses

2d-(7(d+2)+2)-10-4=0



We calculate terms in parentheses: -(7(d+2)+2), so:

7(d+2)+2

We multiply parentheses

7d+14+2

We add all the numbers together, and all the variables

7d+16

Back to the equation:

-(7d+16)



We add all the numbers together, and all the variables

2d-(7d+16)-14=0

We get rid of parentheses

2d-7d-16-14=0

We add all the numbers together, and all the variables

-5d-30=0

We move all terms containing d to the left, all other terms to the right

-5d=30

d=30/-5

d=-6

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