2(d-4)=5(2d+1)

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Solution for 2(d-4)=5(2d+1) equation: 



2(d-4)=5(2d+1)

We move all terms to the left:

2(d-4)-(5(2d+1))=0

We multiply parentheses

2d-(5(2d+1))-8=0



We calculate terms in parentheses: -(5(2d+1)), so:

5(2d+1)

We multiply parentheses

10d+5

Back to the equation:

-(10d+5)



We get rid of parentheses

2d-10d-5-8=0

We add all the numbers together, and all the variables

-8d-13=0

We move all terms containing d to the left, all other terms to the right

-8d=13

d=13/-8

d=-1+5/8

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