2(d-(2d+12)+11)=2(d+1)

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Solution for 2(d-(2d+12)+11)=2(d+1) equation: 



2(d-(2d+12)+11)=2(d+1)

We move all terms to the left:

2(d-(2d+12)+11)-(2(d+1))=0



We calculate terms in parentheses: -(2(d+1)), so:

2(d+1)

We multiply parentheses

2d+2

Back to the equation:

-(2d+2)



We get rid of parentheses

2(d-(2d+12)+11)-2d-2=0

We add all the numbers together, and all the variables

-2d+2(d-(2d+12)+11)-2=0

We move all terms containing d to the left, all other terms to the right

-2d+2(d-(2d+12)+11)=2

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