2(d+5)=32

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Solution for 2(d+5)=32 equation: 



2(d+5)=32

We move all terms to the left:

2(d+5)-(32)=0

We multiply parentheses

2d+10-32=0

We add all the numbers together, and all the variables

2d-22=0

We move all terms containing d to the left, all other terms to the right

2d=22

d=22/2

d=11

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