2(d+24)(d-18)=0

Solution for 2(d+24)(d-18)=0 equation:

2(d+24)(d-18)=0

We multiply parentheses ..

2(+d^2-18d+24d-432)=0

We multiply parentheses

2d^2-36d+48d-864=0

We add all the numbers together, and all the variables

2d^2+12d-864=0

a = 2; b = 12; c = -864;
Δ = b2-4ac
Δ = 122-4·2·(-864)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-84}{2*2}=\frac{-96}{4}
=-24
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+84}{2*2}=\frac{72}{4}
=18
$