2(cos(2x)-sin(x))=0

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Solution for 2(cos(2x)-sin(x))=0 equation:


Simplifying
2(cos(2x) + -1sin(x)) = 0

Remove parenthesis around (2x)
2(cos * 2x + -1sin(x)) = 0

Reorder the terms for easier multiplication:
2(2cos * x + -1sin(x)) = 0

Multiply cos * x
2(2cosx + -1sin(x)) = 0

Multiply ins * x
2(2cosx + -1insx) = 0
(2cosx * 2 + -1insx * 2) = 0
(4cosx + -2insx) = 0

Solving
4cosx + -2insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2insx' to each side of the equation.
4cosx + -2insx + 2insx = 0 + 2insx

Combine like terms: -2insx + 2insx = 0
4cosx + 0 = 0 + 2insx
4cosx = 0 + 2insx
Remove the zero:
4cosx = 2insx

Divide each side by '4osx'.
c = 0.5ino-1

Simplifying
c = 0.5ino-1

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