2(c-d)+(c-3d)+5(c-d)=

Solution for 2(c-d)+(c-3d)+5(c-d)= equation:

Simplifying
2(c + -1d) + (c + -3d) + 5(c + -1d) = 0
(c * 2 + -1d * 2) + (c + -3d) + 5(c + -1d) = 0
(2c + -2d) + (c + -3d) + 5(c + -1d) = 0

Remove parenthesis around (c + -3d)
2c + -2d + c + -3d + 5(c + -1d) = 0
2c + -2d + c + -3d + (c * 5 + -1d * 5) = 0
2c + -2d + c + -3d + (5c + -5d) = 0

Reorder the terms:
2c + c + 5c + -2d + -3d + -5d = 0

Combine like terms: 2c + c = 3c
3c + 5c + -2d + -3d + -5d = 0

Combine like terms: 3c + 5c = 8c
8c + -2d + -3d + -5d = 0

Combine like terms: -2d + -3d = -5d
8c + -5d + -5d = 0

Combine like terms: -5d + -5d = -10d
8c + -10d = 0

Solving
8c + -10d = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '10d' to each side of the equation.
8c + -10d + 10d = 0 + 10d

Combine like terms: -10d + 10d = 0
8c + 0 = 0 + 10d
8c = 0 + 10d
Remove the zero:
8c = 10d

Divide each side by '8'.
c = 1.25d

Simplifying
c = 1.25d