2(c-7)=6c+10

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Solution for 2(c-7)=6c+10 equation: 



2(c-7)=6c+10

We move all terms to the left:

2(c-7)-(6c+10)=0

We multiply parentheses

2c-(6c+10)-14=0

We get rid of parentheses

2c-6c-10-14=0

We add all the numbers together, and all the variables

-4c-24=0

We move all terms containing c to the left, all other terms to the right

-4c=24

c=24/-4

c=-6

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