2(c-7)=10(c-3)

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Solution for 2(c-7)=10(c-3) equation: 



2(c-7)=10(c-3)

We move all terms to the left:

2(c-7)-(10(c-3))=0

We multiply parentheses

2c-(10(c-3))-14=0



We calculate terms in parentheses: -(10(c-3)), so:

10(c-3)

We multiply parentheses

10c-30

Back to the equation:

-(10c-30)



We get rid of parentheses

2c-10c+30-14=0

We add all the numbers together, and all the variables

-8c+16=0

We move all terms containing c to the left, all other terms to the right

-8c=-16

c=-16/-8

c=+2

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