2(c-4)=3(1+c)

Solution for 2(c-4)=3(1+c) equation:

2(c-4)=3(1+c)

We move all terms to the left:

2(c-4)-(3(1+c))=0

We add all the numbers together, and all the variables

2(c-4)-(3(c+1))=0

We multiply parentheses

2c-(3(c+1))-8=0


We calculate terms in parentheses: -(3(c+1)), so:

3(c+1)

We multiply parentheses

3c+3

Back to the equation:

-(3c+3)


We get rid of parentheses

2c-3c-3-8=0

We add all the numbers together, and all the variables

-1c-11=0

We move all terms containing c to the left, all other terms to the right

-c=11

c=11/-1

c=-11