2(c-4)+8=1/2(6c+20

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Solution for 2(c-4)+8=1/2(6c+20 equation: 



2(c-4)+8=1/2(6c+20

We move all terms to the left:

2(c-4)+8-(1/2(6c+20)=0



Domain of the equation: 2(6c+20)+8!=0

We move all terms containing c to the left, all other terms to the right

2(6c+20)!=-8

c∈R



We multiply parentheses

2c-(1/2(6c+20)+8-8=0

We multiply all the terms by the denominator


2c*2(6c+20)+8-8-(1=0

We add all the numbers together, and all the variables

2c*2(6c+20)=0

Wy multiply elements

4c^2(6=0

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