2(c-30)+5c=30+2(2c+60)

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Solution for 2(c-30)+5c=30+2(2c+60) equation: 



2(c-30)+5c=30+2(2c+60)

We move all terms to the left:

2(c-30)+5c-(30+2(2c+60))=0

We add all the numbers together, and all the variables

5c+2(c-30)-(30+2(2c+60))=0

We multiply parentheses

5c+2c-(30+2(2c+60))-60=0



We calculate terms in parentheses: -(30+2(2c+60)), so:

30+2(2c+60)

determiningTheFunctionDomain
2(2c+60)+30

We multiply parentheses

4c+120+30

We add all the numbers together, and all the variables

4c+150

Back to the equation:

-(4c+150)



We add all the numbers together, and all the variables

7c-(4c+150)-60=0

We get rid of parentheses

7c-4c-150-60=0

We add all the numbers together, and all the variables

3c-210=0

We move all terms containing c to the left, all other terms to the right

3c=210

c=210/3

c=70

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