2(c-2)=3(c-2)

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Solution for 2(c-2)=3(c-2) equation: 



2(c-2)=3(c-2)

We move all terms to the left:

2(c-2)-(3(c-2))=0

We multiply parentheses

2c-(3(c-2))-4=0



We calculate terms in parentheses: -(3(c-2)), so:

3(c-2)

We multiply parentheses

3c-6

Back to the equation:

-(3c-6)



We get rid of parentheses

2c-3c+6-4=0

We add all the numbers together, and all the variables

-1c+2=0

We move all terms containing c to the left, all other terms to the right

-c=-2

c=-2/-1

c=+2

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