2(c+3)=33-c

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Solution for 2(c+3)=33-c equation: 



2(c+3)=33-c

We move all terms to the left:

2(c+3)-(33-c)=0

We add all the numbers together, and all the variables

2(c+3)-(-1c+33)=0

We multiply parentheses

2c-(-1c+33)+6=0

We get rid of parentheses

2c+1c-33+6=0

We add all the numbers together, and all the variables

3c-27=0

We move all terms containing c to the left, all other terms to the right

3c=27

c=27/3

c=9

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