2(c+3)+3c=26

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Solution for 2(c+3)+3c=26 equation: 



2(c+3)+3c=26

We move all terms to the left:

2(c+3)+3c-(26)=0

We add all the numbers together, and all the variables

3c+2(c+3)-26=0

We multiply parentheses

3c+2c+6-26=0

We add all the numbers together, and all the variables

5c-20=0

We move all terms containing c to the left, all other terms to the right

5c=20

c=20/5

c=4

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