2(c+20)=5(c+1)-7

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Solution for 2(c+20)=5(c+1)-7 equation: 


Simplifying
2(c + 20) = 5(c + 1) + -7

Reorder the terms:
2(20 + c) = 5(c + 1) + -7
(20 * 2 + c * 2) = 5(c + 1) + -7
(40 + 2c) = 5(c + 1) + -7

Reorder the terms:
40 + 2c = 5(1 + c) + -7
40 + 2c = (1 * 5 + c * 5) + -7
40 + 2c = (5 + 5c) + -7

Reorder the terms:
40 + 2c = 5 + -7 + 5c

Combine like terms: 5 + -7 = -2
40 + 2c = -2 + 5c

Solving
40 + 2c = -2 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
40 + 2c + -5c = -2 + 5c + -5c

Combine like terms: 2c + -5c = -3c
40 + -3c = -2 + 5c + -5c

Combine like terms: 5c + -5c = 0
40 + -3c = -2 + 0
40 + -3c = -2

Add '-40' to each side of the equation.
40 + -40 + -3c = -2 + -40

Combine like terms: 40 + -40 = 0
0 + -3c = -2 + -40
-3c = -2 + -40

Combine like terms: -2 + -40 = -42
-3c = -42

Divide each side by '-3'.
c = 14

Simplifying
c = 14

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