2(c+2)=6+2c-2

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Solution for 2(c+2)=6+2c-2 equation: 



2(c+2)=6+2c-2

We move all terms to the left:

2(c+2)-(6+2c-2)=0

We add all the numbers together, and all the variables

2(c+2)-(2c+4)=0

We multiply parentheses

2c-(2c+4)+4=0

We get rid of parentheses

2c-2c-4+4=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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