2(c+2)=3(c-4)

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Solution for 2(c+2)=3(c-4) equation:


Simplifying
2(c + 2) = 3(c + -4)

Reorder the terms:
2(2 + c) = 3(c + -4)
(2 * 2 + c * 2) = 3(c + -4)
(4 + 2c) = 3(c + -4)

Reorder the terms:
4 + 2c = 3(-4 + c)
4 + 2c = (-4 * 3 + c * 3)
4 + 2c = (-12 + 3c)

Solving
4 + 2c = -12 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
4 + 2c + -3c = -12 + 3c + -3c

Combine like terms: 2c + -3c = -1c
4 + -1c = -12 + 3c + -3c

Combine like terms: 3c + -3c = 0
4 + -1c = -12 + 0
4 + -1c = -12

Add '-4' to each side of the equation.
4 + -4 + -1c = -12 + -4

Combine like terms: 4 + -4 = 0
0 + -1c = -12 + -4
-1c = -12 + -4

Combine like terms: -12 + -4 = -16
-1c = -16

Divide each side by '-1'.
c = 16

Simplifying
c = 16

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