2(c+2)=(c+1)-7

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Solution for 2(c+2)=(c+1)-7 equation:


Simplifying
2(c + 2) = (c + 1) + -7

Reorder the terms:
2(2 + c) = (c + 1) + -7
(2 * 2 + c * 2) = (c + 1) + -7
(4 + 2c) = (c + 1) + -7

Reorder the terms:
4 + 2c = (1 + c) + -7

Remove parenthesis around (1 + c)
4 + 2c = 1 + c + -7

Reorder the terms:
4 + 2c = 1 + -7 + c

Combine like terms: 1 + -7 = -6
4 + 2c = -6 + c

Solving
4 + 2c = -6 + c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
4 + 2c + -1c = -6 + c + -1c

Combine like terms: 2c + -1c = 1c
4 + 1c = -6 + c + -1c

Combine like terms: c + -1c = 0
4 + 1c = -6 + 0
4 + 1c = -6

Add '-4' to each side of the equation.
4 + -4 + 1c = -6 + -4

Combine like terms: 4 + -4 = 0
0 + 1c = -6 + -4
1c = -6 + -4

Combine like terms: -6 + -4 = -10
1c = -10

Divide each side by '1'.
c = -10

Simplifying
c = -10

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