2(c+2)-5=3(c+1)

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Solution for 2(c+2)-5=3(c+1) equation: 



2(c+2)-5=3(c+1)

We move all terms to the left:

2(c+2)-5-(3(c+1))=0

We multiply parentheses

2c-(3(c+1))+4-5=0



We calculate terms in parentheses: -(3(c+1)), so:

3(c+1)

We multiply parentheses

3c+3

Back to the equation:

-(3c+3)



We add all the numbers together, and all the variables

2c-(3c+3)-1=0

We get rid of parentheses

2c-3c-3-1=0

We add all the numbers together, and all the variables

-1c-4=0

We move all terms containing c to the left, all other terms to the right

-c=4

c=4/-1

c=-4

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