2(c+1)=102c+1=10

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Solution for 2(c+1)=102c+1=10 equation: 



2(c+1)=102c+1=10

We move all terms to the left:

2(c+1)-(102c+1)=0

We multiply parentheses

2c-(102c+1)+2=0

We get rid of parentheses

2c-102c-1+2=0

We add all the numbers together, and all the variables

-100c+1=0

We move all terms containing c to the left, all other terms to the right

-100c=-1

c=-1/-100

c=1/100

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