2(b-8)=4(b+1)-14

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Solution for 2(b-8)=4(b+1)-14 equation:


Simplifying
2(b + -8) = 4(b + 1) + -14

Reorder the terms:
2(-8 + b) = 4(b + 1) + -14
(-8 * 2 + b * 2) = 4(b + 1) + -14
(-16 + 2b) = 4(b + 1) + -14

Reorder the terms:
-16 + 2b = 4(1 + b) + -14
-16 + 2b = (1 * 4 + b * 4) + -14
-16 + 2b = (4 + 4b) + -14

Reorder the terms:
-16 + 2b = 4 + -14 + 4b

Combine like terms: 4 + -14 = -10
-16 + 2b = -10 + 4b

Solving
-16 + 2b = -10 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
-16 + 2b + -4b = -10 + 4b + -4b

Combine like terms: 2b + -4b = -2b
-16 + -2b = -10 + 4b + -4b

Combine like terms: 4b + -4b = 0
-16 + -2b = -10 + 0
-16 + -2b = -10

Add '16' to each side of the equation.
-16 + 16 + -2b = -10 + 16

Combine like terms: -16 + 16 = 0
0 + -2b = -10 + 16
-2b = -10 + 16

Combine like terms: -10 + 16 = 6
-2b = 6

Divide each side by '-2'.
b = -3

Simplifying
b = -3

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