2(b-5)+3(b-2)=8

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Solution for 2(b-5)+3(b-2)=8 equation: 


Simplifying
2(b + -5) + 3(b + -2) = 8

Reorder the terms:
2(-5 + b) + 3(b + -2) = 8
(-5 * 2 + b * 2) + 3(b + -2) = 8
(-10 + 2b) + 3(b + -2) = 8

Reorder the terms:
-10 + 2b + 3(-2 + b) = 8
-10 + 2b + (-2 * 3 + b * 3) = 8
-10 + 2b + (-6 + 3b) = 8

Reorder the terms:
-10 + -6 + 2b + 3b = 8

Combine like terms: -10 + -6 = -16
-16 + 2b + 3b = 8

Combine like terms: 2b + 3b = 5b
-16 + 5b = 8

Solving
-16 + 5b = 8

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 5b = 8 + 16

Combine like terms: -16 + 16 = 0
0 + 5b = 8 + 16
5b = 8 + 16

Combine like terms: 8 + 16 = 24
5b = 24

Divide each side by '5'.
b = 4.8

Simplifying
b = 4.8

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