2(b-5)+12=3(b-2)+2

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Solution for 2(b-5)+12=3(b-2)+2 equation: 



2(b-5)+12=3(b-2)+2

We move all terms to the left:

2(b-5)+12-(3(b-2)+2)=0

We multiply parentheses

2b-(3(b-2)+2)-10+12=0



We calculate terms in parentheses: -(3(b-2)+2), so:

3(b-2)+2

We multiply parentheses

3b-6+2

We add all the numbers together, and all the variables

3b-4

Back to the equation:

-(3b-4)



We add all the numbers together, and all the variables

2b-(3b-4)+2=0

We get rid of parentheses

2b-3b+4+2=0

We add all the numbers together, and all the variables

-1b+6=0

We move all terms containing b to the left, all other terms to the right

-b=-6

b=-6/-1

b=+6

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