2(b-4)=4(1+b)+b

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Solution for 2(b-4)=4(1+b)+b equation: 



2(b-4)=4(1+b)+b

We move all terms to the left:

2(b-4)-(4(1+b)+b)=0

We add all the numbers together, and all the variables

2(b-4)-(4(b+1)+b)=0

We multiply parentheses

2b-(4(b+1)+b)-8=0



We calculate terms in parentheses: -(4(b+1)+b), so:

4(b+1)+b

We add all the numbers together, and all the variables

b+4(b+1)

We multiply parentheses

b+4b+4

We add all the numbers together, and all the variables

5b+4

Back to the equation:

-(5b+4)



We get rid of parentheses

2b-5b-4-8=0

We add all the numbers together, and all the variables

-3b-12=0

We move all terms containing b to the left, all other terms to the right

-3b=12

b=12/-3

b=-4

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