2(b-4)=22-4b

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Solution for 2(b-4)=22-4b equation: 



2(b-4)=22-4b

We move all terms to the left:

2(b-4)-(22-4b)=0

We add all the numbers together, and all the variables

2(b-4)-(-4b+22)=0

We multiply parentheses

2b-(-4b+22)-8=0

We get rid of parentheses

2b+4b-22-8=0

We add all the numbers together, and all the variables

6b-30=0

We move all terms containing b to the left, all other terms to the right

6b=30

b=30/6

b=5

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