2(b-4)-2=3(b-5)

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Solution for 2(b-4)-2=3(b-5) equation: 



2(b-4)-2=3(b-5)

We move all terms to the left:

2(b-4)-2-(3(b-5))=0

We multiply parentheses

2b-(3(b-5))-8-2=0



We calculate terms in parentheses: -(3(b-5)), so:

3(b-5)

We multiply parentheses

3b-15

Back to the equation:

-(3b-15)



We add all the numbers together, and all the variables

2b-(3b-15)-10=0

We get rid of parentheses

2b-3b+15-10=0

We add all the numbers together, and all the variables

-1b+5=0

We move all terms containing b to the left, all other terms to the right

-b=-5

b=-5/-1

b=+5

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