2(b-3)-5=3(b-8)

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Solution for 2(b-3)-5=3(b-8) equation:


Simplifying
2(b + -3) + -5 = 3(b + -8)

Reorder the terms:
2(-3 + b) + -5 = 3(b + -8)
(-3 * 2 + b * 2) + -5 = 3(b + -8)
(-6 + 2b) + -5 = 3(b + -8)

Reorder the terms:
-6 + -5 + 2b = 3(b + -8)

Combine like terms: -6 + -5 = -11
-11 + 2b = 3(b + -8)

Reorder the terms:
-11 + 2b = 3(-8 + b)
-11 + 2b = (-8 * 3 + b * 3)
-11 + 2b = (-24 + 3b)

Solving
-11 + 2b = -24 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-11 + 2b + -3b = -24 + 3b + -3b

Combine like terms: 2b + -3b = -1b
-11 + -1b = -24 + 3b + -3b

Combine like terms: 3b + -3b = 0
-11 + -1b = -24 + 0
-11 + -1b = -24

Add '11' to each side of the equation.
-11 + 11 + -1b = -24 + 11

Combine like terms: -11 + 11 = 0
0 + -1b = -24 + 11
-1b = -24 + 11

Combine like terms: -24 + 11 = -13
-1b = -13

Divide each side by '-1'.
b = 13

Simplifying
b = 13

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