2(b-2)-5=3(b-7)

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Solution for 2(b-2)-5=3(b-7) equation:


Simplifying
2(b + -2) + -5 = 3(b + -7)

Reorder the terms:
2(-2 + b) + -5 = 3(b + -7)
(-2 * 2 + b * 2) + -5 = 3(b + -7)
(-4 + 2b) + -5 = 3(b + -7)

Reorder the terms:
-4 + -5 + 2b = 3(b + -7)

Combine like terms: -4 + -5 = -9
-9 + 2b = 3(b + -7)

Reorder the terms:
-9 + 2b = 3(-7 + b)
-9 + 2b = (-7 * 3 + b * 3)
-9 + 2b = (-21 + 3b)

Solving
-9 + 2b = -21 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-9 + 2b + -3b = -21 + 3b + -3b

Combine like terms: 2b + -3b = -1b
-9 + -1b = -21 + 3b + -3b

Combine like terms: 3b + -3b = 0
-9 + -1b = -21 + 0
-9 + -1b = -21

Add '9' to each side of the equation.
-9 + 9 + -1b = -21 + 9

Combine like terms: -9 + 9 = 0
0 + -1b = -21 + 9
-1b = -21 + 9

Combine like terms: -21 + 9 = -12
-1b = -12

Divide each side by '-1'.
b = 12

Simplifying
b = 12

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