2(b-0.2)=0.8b+2

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Solution for 2(b-0.2)=0.8b+2 equation: 



2(b-0.2)=0.8b+2

We move all terms to the left:

2(b-0.2)-(0.8b+2)=0

We multiply parentheses

2b-(0.8b+2)-0.4=0

We get rid of parentheses

2b-0.8b-2-0.4=0

We add all the numbers together, and all the variables

1.2b-2.4=0

We move all terms containing b to the left, all other terms to the right

1.2b=2.4

b=2.4/1.2

b=2

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