2(b+7/2)=(22)2

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Solution for 2(b+7/2)=(22)2 equation:



2(b+7/2)=(22)2
We move all terms to the left:
2(b+7/2)-((22)2)=0
determiningTheFunctionDomain 2(b+7/2)-222=0
We add all the numbers together, and all the variables
2(+b+7/2)-222=0
We multiply parentheses
2b-222+7/2*2=0
We multiply all the terms by the denominator
2b*2*2+7-222*2*2=0
We add all the numbers together, and all the variables
2b*2*2-881=0
Wy multiply elements
8b*2-881=0
Wy multiply elements
16b-881=0
We move all terms containing b to the left, all other terms to the right
16b=881
b=881/16
b=55+1/16

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