2(b+3c)=

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Solution for 2(b+3c)= equation: 


Simplifying
2(b + 3c) = 0
(b * 2 + 3c * 2) = 0
(2b + 6c) = 0

Solving
2b + 6c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-6c' to each side of the equation.
2b + 6c + -6c = 0 + -6c

Combine like terms: 6c + -6c = 0
2b + 0 = 0 + -6c
2b = 0 + -6c
Remove the zero:
2b = -6c

Divide each side by '2'.
b = -3c

Simplifying
b = -3c

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