2(b+3)=1/2(b-6)

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Solution for 2(b+3)=1/2(b-6) equation: 



2(b+3)=1/2(b-6)

We move all terms to the left:

2(b+3)-(1/2(b-6))=0



Domain of the equation: 2(b-6))!=0

b∈R



We multiply parentheses

2b-(1/2(b-6))+6=0

We multiply all the terms by the denominator


2b*2(b-6))-(1+6*2(b-6))=0

Wy multiply elements

4b^2(b+12b(b=0

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