2(b+3)-(9+b)=2

Solution for 2(b+3)-(9+b)=2 equation:

Simplifying
2(b + 3) + -1(9 + b) = 2

Reorder the terms:
2(3 + b) + -1(9 + b) = 2
(3 * 2 + b * 2) + -1(9 + b) = 2
(6 + 2b) + -1(9 + b) = 2
6 + 2b + (9 * -1 + b * -1) = 2
6 + 2b + (-9 + -1b) = 2

Reorder the terms:
6 + -9 + 2b + -1b = 2

Combine like terms: 6 + -9 = -3
-3 + 2b + -1b = 2

Combine like terms: 2b + -1b = 1b
-3 + 1b = 2

Solving
-3 + 1b = 2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 1b = 2 + 3

Combine like terms: -3 + 3 = 0
0 + 1b = 2 + 3
1b = 2 + 3

Combine like terms: 2 + 3 = 5
1b = 5

Divide each side by '1'.
b = 5

Simplifying
b = 5