2(b+3)+(6-b)=0

Solution for 2(b+3)+(6-b)=0 equation:

Simplifying
2(b + 3) + (6 + -1b) = 0

Reorder the terms:
2(3 + b) + (6 + -1b) = 0
(3 * 2 + b * 2) + (6 + -1b) = 0
(6 + 2b) + (6 + -1b) = 0

Remove parenthesis around (6 + -1b)
6 + 2b + 6 + -1b = 0

Reorder the terms:
6 + 6 + 2b + -1b = 0

Combine like terms: 6 + 6 = 12
12 + 2b + -1b = 0

Combine like terms: 2b + -1b = 1b
12 + 1b = 0

Solving
12 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 1b = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 1b = 0 + -12
1b = 0 + -12

Combine like terms: 0 + -12 = -12
1b = -12

Divide each side by '1'.
b = -12

Simplifying
b = -12