2(b+2)-4=2(b+1)-b+2

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Solution for 2(b+2)-4=2(b+1)-b+2 equation:


Simplifying
2(b + 2) + -4 = 2(b + 1) + -1b + 2

Reorder the terms:
2(2 + b) + -4 = 2(b + 1) + -1b + 2
(2 * 2 + b * 2) + -4 = 2(b + 1) + -1b + 2
(4 + 2b) + -4 = 2(b + 1) + -1b + 2

Reorder the terms:
4 + -4 + 2b = 2(b + 1) + -1b + 2

Combine like terms: 4 + -4 = 0
0 + 2b = 2(b + 1) + -1b + 2
2b = 2(b + 1) + -1b + 2

Reorder the terms:
2b = 2(1 + b) + -1b + 2
2b = (1 * 2 + b * 2) + -1b + 2
2b = (2 + 2b) + -1b + 2

Reorder the terms:
2b = 2 + 2 + 2b + -1b

Combine like terms: 2 + 2 = 4
2b = 4 + 2b + -1b

Combine like terms: 2b + -1b = 1b
2b = 4 + 1b

Solving
2b = 4 + 1b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
2b + -1b = 4 + 1b + -1b

Combine like terms: 2b + -1b = 1b
1b = 4 + 1b + -1b

Combine like terms: 1b + -1b = 0
1b = 4 + 0
1b = 4

Divide each side by '1'.
b = 4

Simplifying
b = 4

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