2(b+2)+b=(6+b)+1

Solution for 2(b+2)+b=(6+b)+1 equation:

2(b+2)+b=(6+b)+1

We move all terms to the left:

2(b+2)+b-((6+b)+1)=0

We add all the numbers together, and all the variables

2(b+2)+b-((b+6)+1)=0

We add all the numbers together, and all the variables

b+2(b+2)-((b+6)+1)=0

We multiply parentheses

b+2b-((b+6)+1)+4=0


We calculate terms in parentheses: -((b+6)+1), so:

(b+6)+1

We get rid of parentheses

b+6+1

We add all the numbers together, and all the variables

b+7

Back to the equation:

-(b+7)


We add all the numbers together, and all the variables

3b-(b+7)+4=0

We get rid of parentheses

3b-b-7+4=0

We add all the numbers together, and all the variables

2b-3=0

We move all terms containing b to the left, all other terms to the right

2b=3

b=3/2

b=1+1/2