2(b+2)+4b-5=7(b+1)-1

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Solution for 2(b+2)+4b-5=7(b+1)-1 equation: 



2(b+2)+4b-5=7(b+1)-1

We move all terms to the left:

2(b+2)+4b-5-(7(b+1)-1)=0

We add all the numbers together, and all the variables

4b+2(b+2)-(7(b+1)-1)-5=0

We multiply parentheses

4b+2b-(7(b+1)-1)+4-5=0



We calculate terms in parentheses: -(7(b+1)-1), so:

7(b+1)-1

We multiply parentheses

7b+7-1

We add all the numbers together, and all the variables

7b+6

Back to the equation:

-(7b+6)



We add all the numbers together, and all the variables

6b-(7b+6)-1=0

We get rid of parentheses

6b-7b-6-1=0

We add all the numbers together, and all the variables

-1b-7=0

We move all terms containing b to the left, all other terms to the right

-b=7

b=7/-1

b=-7

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