2(b+2)+(3b-8)=16

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Solution for 2(b+2)+(3b-8)=16 equation: 


Simplifying
2(b + 2) + (3b + -8) = 16

Reorder the terms:
2(2 + b) + (3b + -8) = 16
(2 * 2 + b * 2) + (3b + -8) = 16
(4 + 2b) + (3b + -8) = 16

Reorder the terms:
4 + 2b + (-8 + 3b) = 16

Remove parenthesis around (-8 + 3b)
4 + 2b + -8 + 3b = 16

Reorder the terms:
4 + -8 + 2b + 3b = 16

Combine like terms: 4 + -8 = -4
-4 + 2b + 3b = 16

Combine like terms: 2b + 3b = 5b
-4 + 5b = 16

Solving
-4 + 5b = 16

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 5b = 16 + 4

Combine like terms: -4 + 4 = 0
0 + 5b = 16 + 4
5b = 16 + 4

Combine like terms: 16 + 4 = 20
5b = 20

Divide each side by '5'.
b = 4

Simplifying
b = 4

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