2(b+1)+3b=3(b+4)

Solution for 2(b+1)+3b=3(b+4) equation:

Simplifying
2(b + 1) + 3b = 3(b + 4)

Reorder the terms:
2(1 + b) + 3b = 3(b + 4)
(1 * 2 + b * 2) + 3b = 3(b + 4)
(2 + 2b) + 3b = 3(b + 4)

Combine like terms: 2b + 3b = 5b
2 + 5b = 3(b + 4)

Reorder the terms:
2 + 5b = 3(4 + b)
2 + 5b = (4 * 3 + b * 3)
2 + 5b = (12 + 3b)

Solving
2 + 5b = 12 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
2 + 5b + -3b = 12 + 3b + -3b

Combine like terms: 5b + -3b = 2b
2 + 2b = 12 + 3b + -3b

Combine like terms: 3b + -3b = 0
2 + 2b = 12 + 0
2 + 2b = 12

Add '-2' to each side of the equation.
2 + -2 + 2b = 12 + -2

Combine like terms: 2 + -2 = 0
0 + 2b = 12 + -2
2b = 12 + -2

Combine like terms: 12 + -2 = 10
2b = 10

Divide each side by '2'.
b = 5

Simplifying
b = 5