2(a-5)=10a+1

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Solution for 2(a-5)=10a+1 equation: 



2(a-5)=10a+1

We move all terms to the left:

2(a-5)-(10a+1)=0

We multiply parentheses

2a-(10a+1)-10=0

We get rid of parentheses

2a-10a-1-10=0

We add all the numbers together, and all the variables

-8a-11=0

We move all terms containing a to the left, all other terms to the right

-8a=11

a=11/-8

a=-1+3/8

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