2(a-3)=1/2(10a-12)

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Solution for 2(a-3)=1/2(10a-12) equation: 



2(a-3)=1/2(10a-12)

We move all terms to the left:

2(a-3)-(1/2(10a-12))=0



Domain of the equation: 2(10a-12))!=0

a∈R



We multiply parentheses

2a-(1/2(10a-12))-6=0

We multiply all the terms by the denominator


2a*2(10a-12))-(1-6*2(10a-12))=0

Wy multiply elements

4a^2(1-12a(1=0

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