2(a-1)-(10a-5)=11-12a+2+3a

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Solution for 2(a-1)-(10a-5)=11-12a+2+3a equation: 



2(a-1)-(10a-5)=11-12a+2+3a

We move all terms to the left:

2(a-1)-(10a-5)-(11-12a+2+3a)=0

We add all the numbers together, and all the variables

2(a-1)-(10a-5)-(-9a+13)=0

We multiply parentheses

2a-(10a-5)-(-9a+13)-2=0

We get rid of parentheses

2a-10a+9a+5-13-2=0

We add all the numbers together, and all the variables

a-10=0

We move all terms containing a to the left, all other terms to the right

a=10

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