2(a-1)+5(9+2)=10(a+2)+3

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Solution for 2(a-1)+5(9+2)=10(a+2)+3 equation: 



2(a-1)+5(9+2)=10(a+2)+3

We move all terms to the left:

2(a-1)+5(9+2)-(10(a+2)+3)=0

We add all the numbers together, and all the variables

2(a-1)-(10(a+2)+3)+511=0

We multiply parentheses

2a-(10(a+2)+3)-2+511=0



We calculate terms in parentheses: -(10(a+2)+3), so:

10(a+2)+3

We multiply parentheses

10a+20+3

We add all the numbers together, and all the variables

10a+23

Back to the equation:

-(10a+23)



We add all the numbers together, and all the variables

2a-(10a+23)+509=0

We get rid of parentheses

2a-10a-23+509=0

We add all the numbers together, and all the variables

-8a+486=0

We move all terms containing a to the left, all other terms to the right

-8a=-486

a=-486/-8

a=60+3/4

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