2(a+4)=2(a-4)+4z

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Solution for 2(a+4)=2(a-4)+4z equation:


Simplifying
2(a + 4) = 2(a + -4) + 4z

Reorder the terms:
2(4 + a) = 2(a + -4) + 4z
(4 * 2 + a * 2) = 2(a + -4) + 4z
(8 + 2a) = 2(a + -4) + 4z

Reorder the terms:
8 + 2a = 2(-4 + a) + 4z
8 + 2a = (-4 * 2 + a * 2) + 4z
8 + 2a = (-8 + 2a) + 4z

Add '-2a' to each side of the equation.
8 + 2a + -2a = -8 + 2a + -2a + 4z

Combine like terms: 2a + -2a = 0
8 + 0 = -8 + 2a + -2a + 4z
8 = -8 + 2a + -2a + 4z

Combine like terms: 2a + -2a = 0
8 = -8 + 0 + 4z
8 = -8 + 4z

Solving
8 = -8 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
8 + -4z = -8 + 4z + -4z

Combine like terms: 4z + -4z = 0
8 + -4z = -8 + 0
8 + -4z = -8

Add '-8' to each side of the equation.
8 + -8 + -4z = -8 + -8

Combine like terms: 8 + -8 = 0
0 + -4z = -8 + -8
-4z = -8 + -8

Combine like terms: -8 + -8 = -16
-4z = -16

Divide each side by '-4'.
z = 4

Simplifying
z = 4

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