2(a+3)+(4s-5)=148

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Solution for 2(a+3)+(4s-5)=148 equation:


Simplifying
2(a + 3) + (4s + -5) = 148

Reorder the terms:
2(3 + a) + (4s + -5) = 148
(3 * 2 + a * 2) + (4s + -5) = 148
(6 + 2a) + (4s + -5) = 148

Reorder the terms:
6 + 2a + (-5 + 4s) = 148

Remove parenthesis around (-5 + 4s)
6 + 2a + -5 + 4s = 148

Reorder the terms:
6 + -5 + 2a + 4s = 148

Combine like terms: 6 + -5 = 1
1 + 2a + 4s = 148

Solving
1 + 2a + 4s = 148

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 2a + -1 + 4s = 148 + -1

Reorder the terms:
1 + -1 + 2a + 4s = 148 + -1

Combine like terms: 1 + -1 = 0
0 + 2a + 4s = 148 + -1
2a + 4s = 148 + -1

Combine like terms: 148 + -1 = 147
2a + 4s = 147

Add '-4s' to each side of the equation.
2a + 4s + -4s = 147 + -4s

Combine like terms: 4s + -4s = 0
2a + 0 = 147 + -4s
2a = 147 + -4s

Divide each side by '2'.
a = 73.5 + -2s

Simplifying
a = 73.5 + -2s

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