2(X-12)=-40+5(-4x-1)

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Solution for 2(X-12)=-40+5(-4x-1) equation: 



2(X-12)=-40+5(-4X-1)

We move all terms to the left:

2(X-12)-(-40+5(-4X-1))=0

We multiply parentheses

2X-(-40+5(-4X-1))-24=0



We calculate terms in parentheses: -(-40+5(-4X-1)), so:

-40+5(-4X-1)

determiningTheFunctionDomain
5(-4X-1)-40

We multiply parentheses

-20X-5-40

We add all the numbers together, and all the variables

-20X-45

Back to the equation:

-(-20X-45)



We get rid of parentheses

2X+20X+45-24=0

We add all the numbers together, and all the variables

22X+21=0

We move all terms containing X to the left, all other terms to the right

22X=-21

X=-21/22

X=-21/22

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