2(I0-2x)=4(2x+2)

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Solution for 2(I0-2x)=4(2x+2) equation: 



2(0-2I)=4(2I+2)

We move all terms to the left:

2(0-2I)-(4(2I+2))=0

We add all the numbers together, and all the variables

2(-2I)-(4(2I+2))=0

We multiply parentheses

-4I-(4(2I+2))=0



We calculate terms in parentheses: -(4(2I+2)), so:

4(2I+2)

We multiply parentheses

8I+8

Back to the equation:

-(8I+8)



We get rid of parentheses

-4I-8I-8=0

We add all the numbers together, and all the variables

-12I-8=0

We move all terms containing I to the left, all other terms to the right

-12I=8

I=8/-12

I=-2/3

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