2(H-4)=-1/2(24-6h)

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Solution for 2(H-4)=-1/2(24-6h) equation: 



2(-4)=-1/2(24-6H)

We move all terms to the left:

2(-4)-(-1/2(24-6H))=0



Domain of the equation: 2(24-6H))!=0

H∈R



We add all the numbers together, and all the variables

-(-1/2(-6H+24))+2(-4)=0

We add all the numbers together, and all the variables

-(-1/2(-6H+24))-8=0

We multiply all the terms by the denominator


-(-1-8*2(-6H+24))=0



We calculate terms in parentheses: -(-1-8*2(-6H+24)), so:

-1-8*2(-6H+24)

determiningTheFunctionDomain
-8*2(-6H+24)-1

Wy multiply elements

-16H(--1

We use the square of the difference formula

-16H(+1

Back to the equation:

-(-16H(+1)



We add all the numbers together, and all the variables

-(-16H1=0

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